What is expand ((x+3)(x+6)^2(x+1))/((x-3)(x+4)) ?

The solution to expand ((x+3)(x+6)^2(x+1))/((x-3)(x+4)) is (x^4+16x^3+87x^2+180x+108)/(x^2+x-12)

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expand ((x+3)(x+6)^2(x+1))/((x-3)(x+4))

expand

\frac{( x + 3 ) ( x + 6 ) ^{2} ( x + 1 )}{( x - 3 ) ( x + 4 )}

\frac{x ^{4} + 16 x ^{3} + 87 x ^{2} + 180 x + 108}{x ^{2} + x - 12}

Solution steps

\frac{( x + 3 ) ( x + 6 ) ^{2} ( x + 1 )}{( x - 3 ) ( x + 4 )}

(x + 6)^{2} = x^{2} + 12 x + 36

= \frac{( x + 3 ) ( x ^{2} + 12 x + 36 ) ( x + 1 )}{( x - 3 ) ( x + 4 )}

Expand

(x - 3) (x + 4) : x^{2} + x - 12

= \frac{( x + 3 ) ( x ^{2} + 12 x + 36 ) ( x + 1 )}{x ^{2} + x - 12}

Expand

(x + 3) (x^{2} + 12 x + 36) (x + 1) : x^{4} + 16 x^{3} + 87 x^{2} + 180 x + 108

= \frac{x ^{4} + 16 x ^{3} + 87 x ^{2} + 180 x + 108}{x ^{2} + x - 12}

0.0759 \cdot 2. 1^{5} \cdot (1 - (0, 5)^{2})

\frac{5 x + 1}{( x + 2 ) ( x - 1 )}

(e^{20 x} + e^{- 20 x})^{2}

lo g_{10} (3) (x + 1) - 2

9 (x + 2 = 4 x - 32)

What is expand ((x+3)(x+6)^2(x+1))/((x-3)(x+4)) ?
The solution to expand ((x+3)(x+6)^2(x+1))/((x-3)(x+4)) is (x^4+16x^3+87x^2+180x+108)/(x^2+x-12)