What is expand log_{10}(3)(x+1)-2 ?

The solution to expand log_{10}(3)(x+1)-2 is log_{10}(3)x+log_{10}(3)-2

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expand log_{10}(3)(x+1)-2

expand

lo g_{10} (3) (x + 1) - 2

lo g_{10} (3) x + lo g_{10} (3) - 2

Solution steps

lo g_{10} (3) (x + 1) - 2

Apply the distributive law:

a (b + c) = ab + a c

lo g_{10} (3) (x + 1) = lo g_{10} (3) x + lo g_{10} (3) \cdot 1

= lo g_{10} (3) x + lo g_{10} (3) \cdot 1 - 2

Apply rule:

a \cdot 1 = a

lo g_{10} (3) \cdot 1 = lo g_{10} (3)

= lo g_{10} (3) x + lo g_{10} (3) - 2

9 (x + 2 = 4 x - 32)

- \frac{8 e ^{x}}{( e ^{x} + 2 ) ^{2}} + 1

(z - 1 - i)^{2}

(sin (t^{3}) - 5 cos (t^{4}) + t^{4}) \cdot (3 t^{2} - 4 t^{3})

- \frac{1}{x ^{2}} + \frac{1}{ln ^{2} ( 1 + x ) ( 1 + x )}

What is expand log_{10}(3)(x+1)-2 ?
The solution to expand log_{10}(3)(x+1)-2 is log_{10}(3)x+log_{10}(3)-2