What is expand ((2(n+1))!)/(2^{n+1)(n+1)!(n+1)} ?

The solution to expand ((2(n+1))!)/(2^{n+1)(n+1)!(n+1)} is ((2n+2)!)/(2^{n+1)n(n+1)!+2^{n+1}(n+1)!}

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expand ((2(n+1))!)/(2^{n+1)(n+1)!(n+1)}

expand

\frac{( 2 ( n + 1 ) ) !}{2 ^{n + 1} ( n + 1 ) ! ( n + 1 )}

\frac{( 2 n + 2 ) !}{2 ^{n + 1} n ( n + 1 ) ! + 2 ^{n + 1} ( n + 1 ) !}

Solution steps

\frac{( 2 ( n + 1 ) ) !}{2 ^{n + 1} ( n + 1 ) ! ( n + 1 )}

Expand

2^{n + 1} (n + 1)! (n + 1) : 2^{n + 1} n (n + 1)! + 2^{n + 1} (n + 1)!

= \frac{( 2 ( n + 1 ) ) !}{2 ^{n + 1} n ( n + 1 ) ! + 2 ^{n + 1} ( n + 1 ) !}

Expand

2 (n + 1) : 2 n + 2

= \frac{( 2 n + 2 ) !}{2 ^{n + 1} n ( n + 1 ) ! + 2 ^{n + 1} ( n + 1 ) !}

\frac{- x ^{2} + 2 x + 3}{( x ^{2} + 3 ) ^{2}}

\frac{20 ( 249 - 2 )}{49}

(x^{3} - 4 x^{2} + x - 4) (x^{2} = 18 x + 82)

\frac{( x ) ( 2 x + 1 )}{2}

x^{3} + 10 x^{2} + 23 x^{1} + 14

What is expand ((2(n+1))!)/(2^{n+1)(n+1)!(n+1)} ?
The solution to expand ((2(n+1))!)/(2^{n+1)(n+1)!(n+1)} is ((2n+2)!)/(2^{n+1)n(n+1)!+2^{n+1}(n+1)!}