What is expand rsin(θ)(e^{r^2cos(θ)}+rsin(θ)) ?

The solution to expand rsin(θ)(e^{r^2cos(θ)}+rsin(θ)) is e^{r^2cos(θ)}rsin(θ)+r^2sin^2(θ)

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expand rsin(θ)(e^{r^2cos(θ)}+rsin(θ))

expand

r sin (θ) (e^{r^{2} c o s (θ)} + r sin (θ))

e^{r^{2} c o s (θ)} r sin (θ) + r^{2} sin^{2} (θ)

Solution steps

r sin (θ) (e^{r^{2} c o s (θ)} + r sin (θ))

Apply the distributive law:

a (b + c) = ab + a c

a = r sin (θ), b = e^{r^{2} c o s (θ)}, c = r sin (θ)

= r sin (θ) e^{r^{2} c o s (θ)} + r sin (θ) r sin (θ)

= e^{r^{2} c o s (θ)} r sin (θ) + rr sin (θ) sin (θ)

rr sin (θ) sin (θ) = r^{2} sin^{2} (θ)

= e^{r^{2} c o s (θ)} r sin (θ) + r^{2} sin^{2} (θ)

(e^{t} + e^{- t})^{2}

\frac{2 ( - 3 x ^{2} + 7 )}{( 3 x ^{2} + 7 ) ^{2}}

\frac{8}{( e ^{2 x} + e ^{- 2 x} ) ^{2}}

p o in t s (42 x - 6 y^{2} - ln ∣ x + y ∣)

\frac{( 4 x - 1 ) ( 2 x ^{2} + x + 2 )}{12}

What is expand rsin(θ)(e^{r^2cos(θ)}+rsin(θ)) ?
The solution to expand rsin(θ)(e^{r^2cos(θ)}+rsin(θ)) is e^{r^2cos(θ)}rsin(θ)+r^2sin^2(θ)