What are the solutions to the equation n^2+2n+1=0 ?

The solutions to the equation n^2+2n+1=0 are n=-1

Find the zeros of n^2+2n+1=0

The zeros of n^2+2n+1=0 are n=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} + 2 n + 1 = 0

n = - 1

Solution steps

n^{2} + 2 n + 1 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

n_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

n = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

n = - 1

The solution to the quadratic equation is:

n = - 1

\frac{4 x - 6}{10} + 2 x = 21 - \frac{3 ( x + 1 )}{12}

y^{2} + 13 y = - 42

5 ∣ 2 x - 1 ∣ = 15

x^{2} - 14 x + 33 = 0

\frac{29}{4} \cdot 2

What are the solutions to the equation n^2+2n+1=0 ?
The solutions to the equation n^2+2n+1=0 are n=-1
Find the zeros of n^2+2n+1=0
The zeros of n^2+2n+1=0 are n=-1