What is expand (2(8x+7))/((3x-1)^3) ?

The solution to expand (2(8x+7))/((3x-1)^3) is (16x+14)/(27x^3-27x^2+9x-1)

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expand (2(8x+7))/((3x-1)^3)

expand

\frac{2 ( 8 x + 7 )}{( 3 x - 1 ) ^{3}}

\frac{16 x + 14}{27 x ^{3} - 27 x ^{2} + 9 x - 1}

Solution steps

\frac{2 ( 8 x + 7 )}{( 3 x - 1 ) ^{3}}

(3 x - 1)^{3} = 27 x^{3} - 27 x^{2} + 9 x - 1

= \frac{2 ( 8 x + 7 )}{27 x ^{3} - 27 x ^{2} + 9 x - 1}

Expand

2 (8 x + 7) : 16 x + 14

= \frac{16 x + 14}{27 x ^{3} - 27 x ^{2} + 9 x - 1}

K + 0.082 K

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(t + 1) d t

(cot (x) + 1) (3 cot (x) + 1 = 0)

(x - 3 + i) (x - 3 - i)

What is expand (2(8x+7))/((3x-1)^3) ?
The solution to expand (2(8x+7))/((3x-1)^3) is (16x+14)/(27x^3-27x^2+9x-1)