What is expand (x-3+i)(x-3-i) ?

The solution to expand (x-3+i)(x-3-i) is x^2-6x+10

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expand (x-3+i)(x-3-i)

expand

(x - 3 + i) (x - 3 - i)

x^{2} - 6 x + 10

Solution steps

(x - 3 + i) (x - 3 - i)

Distribute parentheses

= xx + x (- 3) + x (- i) - 3 x - 3 (- 3) - 3 (- i) + i x + i (- 3) + i (- i)

Simplify

xx + x (- 3) + x (- i) - 3 x - 3 (- 3) - 3 (- i) + i x + i (- 3) + i (- i) : x^{2} - 6 x + 10

= x^{2} - 6 x + 10

\frac{1}{( x + 2 ) ( x + 1 ) ( x - 1 ) ( x ^{2} + 1 )}

r (cos (θ) + j sin (θ))

(t e^{(- 2 t)} + sin (t) + cos (t))^{2} U (t + 6)

(6 - 8.5 sin (x))^{2}

(3 y^{6} + 4) l e f t (9 y^{12} - 12 y^{6} + 16)

What is expand (x-3+i)(x-3-i) ?
The solution to expand (x-3+i)(x-3-i) is x^2-6x+10