What is expand (x^2-5)(x+6)' ?

The solution to expand (x^2-5)(x+6)' is x^2(x+6)'-5(x+6)'

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expand (x^2-5)(x+6)'

expand

(x^{2} - 5) (x + 6)^{'}

x^{2} (x + 6)' - 5 (x + 6)'

Solution steps

(x^{2} - 5) (x + 6)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (x + 6)^{'}, b = x^{2}, c = 5

= (x + 6)^{^{'}} x^{2} - (x + 6)^{^{'}} 5

= x^{2} (x + 6)^{^{'}} - 5 (x + 6)^{^{'}}

(3 cos (3 x) - 2 sin (3 x))^{2}

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- y (y - e^{2})

(1 - w + w^{2} - 1)^{2}

\frac{( x + 1 ) ( x - 1 ) ( x - 2 ) ( x - 3 )}{6}

What is expand (x^2-5)(x+6)' ?
The solution to expand (x^2-5)(x+6)' is x^2(x+6)'-5(x+6)'