What is expand 5(-θ+tan(θ))+c ?

The solution to expand 5(-θ+tan(θ))+c is -5θ+5tan(θ)+c

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expand 5(-θ+tan(θ))+c

expand

5 (- θ + tan (θ)) + c

- 5 θ + 5 tan (θ) + c

Solution steps

5 (- θ + tan (θ)) + c

Apply the distributive law:

a (b + c) = ab + a c

5 (- θ + tan (θ)) = 5 (- θ) + 5 tan (θ)

= 5 (- θ) + 5 tan (θ) + c

Simplify

5 (- θ) : - 5 θ

= - 5 θ + 5 tan (θ) + c

f^{'} (1) (x^{2} - 2 x + \frac{1}{x ^{2}})

\frac{3 ( 5 - 1 )}{4}

(x + C e^{- x} + C e^{- 3 x}) (- 3 e^{x})

(2 + \frac{2 k}{n})^{2}

(5 x^{2} + 3 x) l e f t (2 x^{3} - x^{2})

What is expand 5(-θ+tan(θ))+c ?
The solution to expand 5(-θ+tan(θ))+c is -5θ+5tan(θ)+c