What are the solutions to the equation r^2+8r+20=0 ?

The solutions to the equation r^2+8r+20=0 are r=-4+2i,r=-4-2i

Find the zeros of r^2+8r+20=0

The zeros of r^2+8r+20=0 are r=-4+2i,r=-4-2i

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r^{2} + 8 r + 20 = 0

r = - 4 + 2 i, r = - 4 - 2 i

Solution steps

r^{2} + 8 r + 20 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 20 : 4 i

r_{1, 2} = \frac{- 8 \pm 4 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 8 + 4 i}{2 \cdot 1}, r_{2} = \frac{- 8 - 4 i}{2 \cdot 1}

r = \frac{- 8 + 4 i}{2 \cdot 1} : - 4 + 2 i

r = \frac{- 8 - 4 i}{2 \cdot 1} : - 4 - 2 i

The solutions to the quadratic equation are:

r = - 4 + 2 i, r = - 4 - 2 i

2 x - 2 > 3 x - 8

5 + 3 x = 0

2^{- 7}

(x + 2)^{2} = - 25

- 5 x + 6 \leq - 4 x + 3

What are the solutions to the equation r^2+8r+20=0 ?
The solutions to the equation r^2+8r+20=0 are r=-4+2i,r=-4-2i
Find the zeros of r^2+8r+20=0
The zeros of r^2+8r+20=0 are r=-4+2i,r=-4-2i