What is expand ((a^{n+3}))/(a^{n-5)} ?

The solution to expand ((a^{n+3}))/(a^{n-5)} is a^8

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expand ((a^{n+3}))/(a^{n-5)}

expand

\frac{( a ^{n + 3} )}{a ^{n - 5}}

a^{8}

Solution steps

\frac{a ^{n + 3}}{a ^{n - 5}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{a ^{n + 3}}{a ^{n - 5}} = a^{n + 3 - (n - 5)}

= a^{n + 3 - (n - 5)}

Add similar elements:

n + 3 - (n - 5) = 8

= a^{8}

\frac{( s ( s + 2 ) )}{( s ^{2} + 4 )}

(1 + x^{2}) (\frac{x}{2} - \frac{4}{x})^{6}

\frac{a + 4}{( a + 1 ) a}

(- 2 + i) (i + 1) ((- 2 + i)^{2} + 4 (- 2 + i) + 8)

- (- \frac{2}{5} - \frac{7}{5})

What is expand ((a^{n+3}))/(a^{n-5)} ?
The solution to expand ((a^{n+3}))/(a^{n-5)} is a^8