What is expand (-2+i)(i+1)((-2+i)^2+4(-2+i)+8) ?

The solution to expand (-2+i)(i+1)((-2+i)^2+4(-2+i)+8) is -9-3i

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expand (-2+i)(i+1)((-2+i)^2+4(-2+i)+8)

expand

(- 2 + i) (i + 1) ((- 2 + i)^{2} + 4 (- 2 + i) + 8)

- 9 - 3 i

Solution steps

(- 2 + i) (i + 1) ((- 2 + i)^{2} + 4 (- 2 + i) + 8)

Expand

(- 2 + i) (i + 1) ((- 2 + i)^{2} + 4 (- 2 + i) + 8) : (- i - 3) ((- 2 + i)^{2} + 4 (- 2 + i) + 8)

= (- i - 3) ((- 2 + i)^{2} + 4 (- 2 + i) + 8)

Distribute parentheses

= - i (- 2 + i)^{2} - i 4 (- 2 + i) - i 8 - 3 (- 2 + i)^{2} - 3 \cdot 4 (- 2 + i) - 3 \cdot 8

Simplify

- i (- 2 + i)^{2} - i 4 (- 2 + i) - i 8 - 3 (- 2 + i)^{2} - 3 \cdot 4 (- 2 + i) - 3 \cdot 8 : - 3 i - 9

= - 3 i - 9

Rewrite in standard complex form:

- 9 - 3 i

= - 9 - 3 i

- (- \frac{2}{5} - \frac{7}{5})

\frac{200}{x ( x + 501.98 ) ( x + 8.946 ) ( x + 89.072 )}

\frac{1}{( x ^{2} + 4 ) ( x ^{2} + 9 )}

What is expand (-2+i)(i+1)((-2+i)^2+4(-2+i)+8) ?
The solution to expand (-2+i)(i+1)((-2+i)^2+4(-2+i)+8) is -9-3i