What is expand 1/((x^2+4)(x^2+9)) ?

The solution to expand 1/((x^2+4)(x^2+9)) is 1/(x^4+13x^2+36)

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expand 1/((x^2+4)(x^2+9))

expand

\frac{1}{( x ^{2} + 4 ) ( x ^{2} + 9 )}

\frac{1}{x ^{4} + 13 x ^{2} + 36}

Solution steps

\frac{1}{( x ^{2} + 4 ) ( x ^{2} + 9 )}

Expand

(x^{2} + 4) (x^{2} + 9) : x^{4} + 13 x^{2} + 36

= \frac{1}{x ^{4} + 13 x ^{2} + 36}

(n^{3} + 6 n) lo g_{10} (n^{5} + 4) + n \cdot (n + 7)

\frac{( e ^{x} - e ^{- x} ) ( e ^{x} + e ^{- x} )}{2}

(4 x^{5}) (x^{2})

2 (e^{3} + e^{5} + e^{7} + e^{9})

\frac{( x + 3 ) ( x - 2 )}{( x + 4 ) ( x - 3 )}

What is expand 1/((x^2+4)(x^2+9)) ?
The solution to expand 1/((x^2+4)(x^2+9)) is 1/(x^4+13x^2+36)