What is expand ((x+3)(x-2))/((x+4)(x-3)) ?

The solution to expand ((x+3)(x-2))/((x+4)(x-3)) is (x^2+x-6)/(x^2+x-12)

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expand ((x+3)(x-2))/((x+4)(x-3))

expand

\frac{( x + 3 ) ( x - 2 )}{( x + 4 ) ( x - 3 )}

\frac{x ^{2} + x - 6}{x ^{2} + x - 12}

Solution steps

\frac{( x + 3 ) ( x - 2 )}{( x + 4 ) ( x - 3 )}

Expand

(x + 4) (x - 3) : x^{2} + x - 12

= \frac{( x + 3 ) ( x - 2 )}{x ^{2} + x - 12}

Expand

(x + 3) (x - 2) : x^{2} + x - 6

= \frac{x ^{2} + x - 6}{x ^{2} + x - 12}

\frac{1}{3} (x + 6 = 5 (\frac{x}{3} - 4))

(2 (x - 3))^{2} + 4

- 125 (- 0.2 e^{- 0.2 t} t - e^{- 0.2 t})

(- 5 = 4 u + 2 y (u)) (- 9)

\frac{( 10 - 5 j ) ( 8 + 6 j )}{18 + j}

What is expand ((x+3)(x-2))/((x+4)(x-3)) ?
The solution to expand ((x+3)(x-2))/((x+4)(x-3)) is (x^2+x-6)/(x^2+x-12)