What is expand (x(t^2-16))/(cos^2(t)+1) ?

The solution to expand (x(t^2-16))/(cos^2(t)+1) is (xt^2-16x)/(cos^2(t)+1)

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expand (x(t^2-16))/(cos^2(t)+1)

expand

\frac{x ( t ^{2} - 16 )}{cos ^{2} ( t ) + 1}

\frac{x t ^{2} - 16 x}{cos ^{2} ( t ) + 1}

Solution steps

\frac{x ( t ^{2} - 16 )}{cos ^{2} ( t ) + 1}

Expand

x (t^{2} - 16) : x t^{2} - 16 x

= \frac{x t ^{2} - 16 x}{cos ^{2} ( t ) + 1}

\frac{( x - 3 ) ( x + 3 )}{( x + 2 ) ( x - 2 )}

p (x, y) (t = - \frac{7 π}{6})

- 3 (x + 2) (x - 2)

\frac{1}{( k + 1 ) ln ( k + 1 )}

What is expand (x(t^2-16))/(cos^2(t)+1) ?
The solution to expand (x(t^2-16))/(cos^2(t)+1) is (xt^2-16x)/(cos^2(t)+1)