What is expand 1/2 (-(ln(x))/(5x^5)-1/(25x^5)) ?

The solution to expand 1/2 (-(ln(x))/(5x^5)-1/(25x^5)) is -(ln(x))/(10x^5)-1/(50x^5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/2 (-(ln(x))/(5x^5)-1/(25x^5))

expand

\frac{1}{2} (- \frac{ln ( x )}{5 x ^{5}} - \frac{1}{25 x ^{5}})

- \frac{ln ( x )}{10 x ^{5}} - \frac{1}{50 x ^{5}}

Solution steps

\frac{1}{2} (- \frac{ln ( x )}{5 x ^{5}} - \frac{1}{25 x ^{5}})

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{2}, b = - \frac{ln ( x )}{5 x ^{5}}, c = \frac{1}{25 x ^{5}}

= \frac{1}{2} (- \frac{ln ( x )}{5 x ^{5}}) - \frac{1}{2} \cdot \frac{1}{25 x ^{5}}

Apply minus-plus rules

+ (- a) = - a

= - \frac{1}{2} \cdot \frac{ln ( x )}{5 x ^{5}} - \frac{1}{2} \cdot \frac{1}{25 x ^{5}}

Simplify

- \frac{1}{2} \cdot \frac{ln ( x )}{5 x ^{5}} - \frac{1}{2} \cdot \frac{1}{25 x ^{5}} : - \frac{ln ( x )}{10 x ^{5}} - \frac{1}{50 x ^{5}}

= - \frac{ln ( x )}{10 x ^{5}} - \frac{1}{50 x ^{5}}

3 x + 5 x + 14 x

(x - 1) (x + 2) (x - 10) (x + 10)

(3 m + \frac{12}{m ^{2}} = \frac{3}{2} m - \frac{1}{2} m^{2}) m^{2}

e^{x} sin (2 x) (e^{x} cos (2 x) - 2 e^{x} sin (2 x))

m (m - n)

What is expand 1/2 (-(ln(x))/(5x^5)-1/(25x^5)) ?
The solution to expand 1/2 (-(ln(x))/(5x^5)-1/(25x^5)) is -(ln(x))/(10x^5)-1/(50x^5)