What is expand ((x+2)(2x+3))/3 ?

The solution to expand ((x+2)(2x+3))/3 is (2x^2)/3+(7x)/3+2

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expand ((x+2)(2x+3))/3

expand

\frac{( x + 2 ) ( 2 x + 3 )}{3}

\frac{2 x ^{2}}{3} + \frac{7 x}{3} + 2

Solution steps

\frac{( x + 2 ) ( 2 x + 3 )}{3}

Expand

(x + 2) (2 x + 3) : 2 x^{2} + 7 x + 6

= \frac{2 x ^{2} + 7 x + 6}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + 7 x + 6}{3} = \frac{2 x ^{2}}{3} + \frac{7 x}{3} + \frac{6}{3}

= \frac{2 x ^{2}}{3} + \frac{7 x}{3} + \frac{6}{3}

Divide the numbers:

\frac{6}{3} = 2

= \frac{2 x ^{2}}{3} + \frac{7 x}{3} + 2

2 tan (x + y) sec^{2} (x + y) (1 + z)

\frac{26}{( s + 1 ) ^{3}}

(x + 3) (x - 2 - 3)

x \cdot 10 x

4 (3 x^{2} + 3 x - 1)^{3}

What is expand ((x+2)(2x+3))/3 ?
The solution to expand ((x+2)(2x+3))/3 is (2x^2)/3+(7x)/3+2