What is expand-(4(72-5p^2))/3 ?

The solution to expand-(4(72-5p^2))/3 is (20p^2)/3-96

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expand-(4(72-5p^2))/3

expand

- \frac{4 ( 72 - 5 p ^{2} )}{3}

\frac{20 p ^{2}}{3} - 96

Solution steps

- \frac{4 ( 72 - 5 p ^{2} )}{3}

Expand

4 (72 - 5 p^{2}) : 288 - 20 p^{2}

= - \frac{- 20 p ^{2} + 288}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{288 - 20 p ^{2}}{3} = - (\frac{288}{3}) - (- \frac{20 p ^{2}}{3})

= - (\frac{288}{3}) - (- \frac{20 p ^{2}}{3})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{288}{3} + \frac{20 p ^{2}}{3}

Divide the numbers:

\frac{288}{3} = 96

= - 96 + \frac{20 p ^{2}}{3}

Rewrite in standard form

= \frac{20 p ^{2}}{3} - 96

2 x^{2} (- \frac{1}{x} + 1)

(x + 1) (x + \frac{1}{2}) (x + \frac{1}{4})

(\frac{13}{2} - \frac{2 2 - 1}{3})

(x + h + h)^{2}

(x - \frac{1}{x})^{4} (x + \frac{1}{x})^{2}

What is expand-(4(72-5p^2))/3 ?
The solution to expand-(4(72-5p^2))/3 is (20p^2)/3-96