What is expand (1/x = 5/4-3/(y+1))4 ?

The solution to expand (1/x = 5/4-3/(y+1))4 is 4/x = 5/4-(12)/(y+1)

Popular >

expand (1/x = 5/4-3/(y+1))4

expand

(\frac{1}{x} = \frac{5}{4} - \frac{3}{y + 1}) 4

\frac{4}{x} = \frac{5}{4} - \frac{12}{y + 1}

Solution steps

(\frac{1}{x} = \frac{5}{4} - \frac{3}{y + 1}) \cdot 4

= 4 (\frac{5}{4} = \frac{1}{x} - \frac{3}{y + 1})

Apply the distributive law:

a (b - c) = ab - a c

a = 4, b = \frac{1}{x} = \frac{5}{4}, c = \frac{3}{y + 1}

4 \cdot \frac{1}{x} = \frac{5}{4} - 4 \cdot \frac{3}{y + 1}

Simplify

4 \cdot \frac{1}{x} = \frac{5}{4} - 4 \cdot \frac{3}{y + 1} : \frac{4}{x} = \frac{5}{4} - \frac{12}{y + 1}

\frac{4}{x} = \frac{5}{4} - \frac{12}{y + 1}

(x + 5) (x - 5) (x + 1 - i) (x - 1 - i)

(x - 2 y) d x + 2 (y - x) d y

\frac{2 ( x + 6 )}{x - 2}

\frac{( 6 b + x ) ( b )}{2}

(4 x^{2} + 2 x - 7 \circ 2 x - 1) (x)

What is expand (1/x = 5/4-3/(y+1))4 ?
The solution to expand (1/x = 5/4-3/(y+1))4 is 4/x = 5/4-(12)/(y+1)