What is expand ((((4x^3y^-2)^3)^0)^5)^-4 ?

The solution to expand ((((4x^3y^-2)^3)^0)^5)^-4 is 4

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expand ((((4x^3y^-2)^3)^0)^5)^-4

expand

((((4 x^{3} y^{-} 2)^{3})^{0})^{5})^{-} 4

4

Solution steps

((((4 x^{3} y^{-} \cdot 2)^{3})^{0})^{5})^{-} \cdot 4

Apply rule

a^{0} = 1, a \neq = 0

((4 \cdot 2 x^{3} y^{-})^{3})^{0} = 1

= 4 (1^{5})^{-}

Apply rule

1^{a} = 1

1^{5} = 1

= 4 \cdot 1^{-}

Apply rule

1^{a} = 1

1^{-} = 1

= 1 \cdot 4

Multiply the numbers:

1 \cdot 4 = 4

= 4

(8 x + 5 y = - 7) 6

(x + 2) \times (x - 2)

(y - y + 3)^{2}

\frac{( x - 1 ) ( x - 2 ) ( x - 3 )}{( x - 4 ) ( x - 5 ) ( x - 6 )}

3^{2 (k + 1)}

What is expand ((((4x^3y^-2)^3)^0)^5)^-4 ?
The solution to expand ((((4x^3y^-2)^3)^0)^5)^-4 is 4