What is expand ((2x-3)(x+3))/2 ?

The solution to expand ((2x-3)(x+3))/2 is x^2+(3x)/2-9/2

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expand ((2x-3)(x+3))/2

expand

\frac{( 2 x - 3 ) ( x + 3 )}{2}

x^{2} + \frac{3 x}{2} - \frac{9}{2}

Solution steps

\frac{( 2 x - 3 ) ( x + 3 )}{2}

Expand

(2 x - 3) (x + 3) : 2 x^{2} + 3 x - 9

= \frac{2 x ^{2} + 3 x - 9}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + 3 x - 9}{2} = \frac{2 x ^{2}}{2} + \frac{3 x}{2} - \frac{9}{2}

= \frac{2 x ^{2}}{2} + \frac{3 x}{2} - \frac{9}{2}

Divide the numbers:

\frac{2}{2} = 1

= x^{2} + \frac{3 x}{2} - \frac{9}{2}

\frac{s ^{4} + 26 s ^{2} + 64}{s ( s ^{2} + 4 ) ( s ^{2} + 16 )}

(y^{3})^{2}

\frac{lo g _{10} ( ( x + 1 ) ( x + 4 ) )}{( 2 x + 23 )} - 1

y, 3 x - y = - 22

(x - y = 3, y) (2 x + 4 y = 9)

What is expand ((2x-3)(x+3))/2 ?
The solution to expand ((2x-3)(x+3))/2 is x^2+(3x)/2-9/2