What is expand-12*(x-1)*((x-1)/3) ?

The solution to expand-12*(x-1)*((x-1)/3) is -4x^2+8x-4

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expand-12(x-1)((x-1)/3)

expand

- 12 \cdot (x - 1) \cdot (\frac{x - 1}{3})

- 4 x^{2} + 8 x - 4

Solution steps

- 12 (x - 1) (\frac{x - 1}{3})

Apply rule:

(a) = a

(\frac{x - 1}{3}) = \frac{x - 1}{3}

= - 12 (x - 1) \frac{x - 1}{3}

= - 12 \cdot \frac{x - 1}{3} (x - 1)

Apply the distributive law:

a (b - c) = ab - a c

- 12 \cdot \frac{x - 1}{3} (x - 1) = - 12 \cdot \frac{x - 1}{3} x - (- 12 \cdot \frac{x - 1}{3}) \cdot 1

= - 12 \cdot \frac{x - 1}{3} x - (- 12 \cdot \frac{x - 1}{3}) \cdot 1

Simplify

- 12 \cdot \frac{x - 1}{3} x - (- 12 \cdot \frac{x - 1}{3}) \cdot 1 : - 4 x^{2} + 8 x - 4

= - 4 x^{2} + 8 x - 4

\frac{12 x + 69}{( 2 x ^{2} + 5 ) ( x + 6 )}

\frac{1}{2} + \frac{3}{32} (4 (0.5) - \frac{( 0.5 ) ^{3}}{3})

- 6 (\frac{x}{10} - y)

(z + 2)^{2} (z + 3) - (z + 1)^{\frac{1}{3}}

\frac{1 - 4 sin ( 1 0 ^{\circ} ) sin ( 7 0 ^{\circ} )}{2 sin ( 1 0 ^{\circ} )}

What is expand-12*(x-1)*((x-1)/3) ?
The solution to expand-12*(x-1)*((x-1)/3) is -4x^2+8x-4