What is expand (1-4sin(10)sin(70))/(2sin(10)) ?

The solution to expand (1-4sin(10)sin(70))/(2sin(10)) is 1/(2sin(10))-2sin(70)

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expand (1-4sin(10)sin(70))/(2sin(10))

expand

\frac{1 - 4 sin ( 1 0 ^{\circ} ) sin ( 7 0 ^{\circ} )}{2 sin ( 1 0 ^{\circ} )}

\frac{1}{2 sin ( 1 0 ^{\circ} )} - 2 sin (7 0^{\circ})

Decimal Notation

1

Solution steps

\frac{1 - 4 sin ( 1 0 ^{\circ} ) sin ( 7 0 ^{\circ} )}{2 sin ( 1 0 ^{\circ} )}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 4 sin ( 1 0 ^{\circ} ) sin ( 7 0 ^{\circ} )}{2 sin ( 1 0 ^{\circ} )} = \frac{1}{2 sin ( 1 0 ^{\circ} )} - \frac{4 sin ( 1 0 ^{\circ} ) sin ( 7 0 ^{\circ} )}{2 sin ( 1 0 ^{\circ} )}

= \frac{1}{2 sin ( 1 0 ^{\circ} )} - \frac{4 sin ( 1 0 ^{\circ} ) sin ( 7 0 ^{\circ} )}{2 sin ( 1 0 ^{\circ} )}

Cancel

\frac{4 sin ( 1 0 ^{\circ} ) sin ( 7 0 ^{\circ} )}{2 sin ( 1 0 ^{\circ} )} : 2 sin (7 0^{\circ})

= \frac{1}{2 sin ( 1 0 ^{\circ} )} - 2 sin (7 0^{\circ})

\frac{1}{2} (- \frac{1}{6} cos (6 x) - \frac{1}{2} cos (2 x))

\frac{2 x}{( 2 x - 1 ) ^{2}}

\frac{( ( - 1 ) ^{n} \cdot ( e ^{s} - 1 ) \cdot e ^{- n s - s} )}{s}

(x^{2} + 1 + x)^{2}

2 - x^{2} (2 - x^{2})

What is expand (1-4sin(10)sin(70))/(2sin(10)) ?
The solution to expand (1-4sin(10)sin(70))/(2sin(10)) is 1/(2sin(10))-2sin(70)