What is expand (2(3-2y^2-8y))/3 ?

The solution to expand (2(3-2y^2-8y))/3 is -(4y^2)/3-(16y)/3+2

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expand (2(3-2y^2-8y))/3

expand

\frac{2 ( 3 - 2 y ^{2} - 8 y )}{3}

- \frac{4 y ^{2}}{3} - \frac{16 y}{3} + 2

Solution steps

\frac{2 ( 3 - 2 y ^{2} - 8 y )}{3}

Expand

2 (3 - 2 y^{2} - 8 y) : 6 - 4 y^{2} - 16 y

= \frac{6 - 4 y ^{2} - 16 y}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 - 4 y ^{2} - 16 y}{3} = \frac{6}{3} - \frac{4 y ^{2}}{3} - \frac{16 y}{3}

= \frac{6}{3} - \frac{4 y ^{2}}{3} - \frac{16 y}{3}

Divide the numbers:

\frac{6}{3} = 2

= 2 - \frac{4 y ^{2}}{3} - \frac{16 y}{3}

Rewrite in standard form

= - \frac{4 y ^{2}}{3} - \frac{16 y}{3} + 2

(z^{2} - 1) (z^{2} - 2 + 1) (z^{2} + 1) (z^{2} + 2 + 1)

\frac{12 z ^{2} + 4 z}{3 ( z - 2 ) ( 4 z - 1 )}

\frac{( a + b + c + d ) ^{2}}{4}

\frac{2 ln ( 3 )}{5 ( - e ^{\frac{l n ( 3 )}{20}} + 1 )}

(x + \frac{3}{5}) (x - \frac{2}{5})

What is expand (2(3-2y^2-8y))/3 ?
The solution to expand (2(3-2y^2-8y))/3 is -(4y^2)/3-(16y)/3+2