What is (z^2-1)(z^2-sqrt(2)+1)(z^2+1)(z^2+sqrt(2)+1) ?

The solution to (z^2-1)(z^2-sqrt(2)+1)(z^2+1)(z^2+sqrt(2)+1) is (z^2-1)(z^4+2z^2-1)(z^2+1)

Popular >

simplify (z^2-1)(z^2-sqrt(2)+1)(z^2+1)(z^2+sqrt(2)+1)

simplify

(z^{2} - 1) (z^{2} - 2 + 1) (z^{2} + 1) (z^{2} + 2 + 1)

(z^{2} - 1) (z^{4} + 2 z^{2} - 1) (z^{2} + 1)

Solution steps

(z^{2} - 1) (z^{2} - 2 + 1) (z^{2} + 1) (z^{2} + 2 + 1)

Distribute parentheses

= (z^{2} - 1) (z^{2} z^{2} + z^{2} 2 + z^{2} \cdot 1 - 2 z^{2} - 22 - 2 \cdot 1 + 1 \cdot z^{2} + 1 \cdot 2 + 1 \cdot 1) (z^{2} + 1)

Simplify

z^{2} z^{2} + z^{2} 2 + z^{2} \cdot 1 - 2 z^{2} - 22 - 2 \cdot 1 + 1 \cdot z^{2} + 1 \cdot 2 + 1 \cdot 1 : z^{4} + 2 z^{2} - 1

= (z^{2} - 1) (z^{4} + 2 z^{2} - 1) (z^{2} + 1)

\frac{12 z ^{2} + 4 z}{3 ( z - 2 ) ( 4 z - 1 )}

\frac{( a + b + c + d ) ^{2}}{4}

\frac{2 ln ( 3 )}{5 ( - e ^{\frac{l n ( 3 )}{20}} + 1 )}

(x + \frac{3}{5}) (x - \frac{2}{5})

\frac{( x + 2 ) ( x - 4 )}{2 ( x + 3 ) ( x - 2 )}

What is (z^2-1)(z^2-sqrt(2)+1)(z^2+1)(z^2+sqrt(2)+1) ?
The solution to (z^2-1)(z^2-sqrt(2)+1)(z^2+1)(z^2+sqrt(2)+1) is (z^2-1)(z^4+2z^2-1)(z^2+1)