What is expand 1/((k+1)ln^2(k+1)) ?

The solution to expand 1/((k+1)ln^2(k+1)) is 1/(kln^2(k+1)+ln^2(k+1))

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expand 1/((k+1)ln^2(k+1))

expand

\frac{1}{( k + 1 ) ln ^{2} ( k + 1 )}

\frac{1}{k ln ^{2} ( k + 1 ) + ln ^{2} ( k + 1 )}

Solution steps

\frac{1}{( k + 1 ) ln ^{2} ( k + 1 )}

Expand

(k + 1) ln^{2} (k + 1) : k ln^{2} (k + 1) + ln^{2} (k + 1)

= \frac{1}{k ln ^{2} ( k + 1 ) + ln ^{2} ( k + 1 )}

(- x)^{6}

, x (2 x + 1) (x - 3)

\frac{1}{( n + 3 ) ^{4}}

(2 x - 1 - 5 x - 4)^{2}

(5 x - x^{2}) (2 x - 3) d x

What is expand 1/((k+1)ln^2(k+1)) ?
The solution to expand 1/((k+1)ln^2(k+1)) is 1/(kln^2(k+1)+ln^2(k+1))