What is expand B(-2,3,5)A(2,-1,1) ?

The solution to expand B(-2,3,5)A(2,-1,1) is 2(-2*3*5,,)BA,-1*(-2*3*5,,)BA,1

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expand B(-2,3,5)A(2,-1,1)

expand

B (- 2, 3, 5) A (2, - 1, 1)

2 (- 2 \cdot 3 \cdot 5,,) B A, - 1 \cdot (- 2 \cdot 3 \cdot 5,,) B A, 1

Solution steps

B (- 2, 3, 5) A (2, - 1, 1)

= (- 2 \cdot 3 \cdot 5,,) (2, - 1 \cdot 1,) B A

Apply the distributive law:

a (b - c) = ab - a c

a = B (- 2, 3, 5) A, b = 2,, c = 1, 1

= B (- 2, 3, 5) A \cdot 2, - B (- 2, 3, 5) A \cdot 1, 1

= 2 (- 2 \cdot 3 \cdot 5,,) B A, - 1 \cdot (- 2 \cdot 3 \cdot 5,,) B A, 1

\frac{\partial}{\partial y} ((z) (x^{2} - 5 x + 6 y))

(- 5 - 5 cos (θ))^{2} \cdot \frac{1}{2}

(x - 3) 2 x^{3} - 3 x^{2} - 5 x - 12

(z^{2} - 8) e^{3 - z}

cos (3 t) (u (t - 4 π))

What is expand B(-2,3,5)A(2,-1,1) ?
The solution to expand B(-2,3,5)A(2,-1,1) is 2(-2*3*5,,)BA,-1*(-2*3*5,,)BA,1