What is expand cos(3t)(u(t-4pi)) ?

The solution to expand cos(3t)(u(t-4pi)) is tucos(3t)-4piucos(3t)

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expand cos(3t)(u(t-4pi))

expand

cos (3 t) (u (t - 4 π))

t u cos (3 t) - 4 π u cos (3 t)

Solution steps

cos (3 t) (u (t - 4 π))

Remove parentheses:

(a) = a

= cos (3 t) u (t - 4 π)

= u cos (3 t) (t - 4 π)

Apply the distributive law:

a (b - c) = ab - a c

a = cos (3 t) u, b = t, c = 4 π

= cos (3 t) u t - cos (3 t) u \cdot 4 π

= t u cos (3 t) - 4 π u cos (3 t)

\frac{( 4 x + 1 ) ^{3}}{12}

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\frac{s - 1}{( s + 3 ) ( s ^{2} + 6 s + 13 )}

x^{2} + ((a + e) + (b + i)) x + (c + o)

\frac{x 2 ^{- x - 1} + 4 ^{- x - 1}}{x ( x + 1 )}

What is expand cos(3t)(u(t-4pi)) ?
The solution to expand cos(3t)(u(t-4pi)) is tucos(3t)-4piucos(3t)