What is expand (s-1)/((s+3)(s^2+6s+13)) ?

The solution to expand (s-1)/((s+3)(s^2+6s+13)) is (s-1)/(s^3+9s^2+31s+39)

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expand (s-1)/((s+3)(s^2+6s+13))

expand

\frac{s - 1}{( s + 3 ) ( s ^{2} + 6 s + 13 )}

\frac{s - 1}{s ^{3} + 9 s ^{2} + 31 s + 39}

Solution steps

\frac{s - 1}{( s + 3 ) ( s ^{2} + 6 s + 13 )}

Expand

(s + 3) (s^{2} + 6 s + 13) : s^{3} + 9 s^{2} + 31 s + 39

= \frac{s - 1}{s ^{3} + 9 s ^{2} + 31 s + 39}

x^{2} + ((a + e) + (b + i)) x + (c + o)

\frac{x 2 ^{- x - 1} + 4 ^{- x - 1}}{x ( x + 1 )}

\frac{2 ( π ^{3} + 3 π ^{2} )}{3 π}

\frac{x - 1}{( x + 3 ) ( x - 6 )}

\frac{y x ^{2} - a}{( x + 2 y ) x ^{2}}

What is expand (s-1)/((s+3)(s^2+6s+13)) ?
The solution to expand (s-1)/((s+3)(s^2+6s+13)) is (s-1)/(s^3+9s^2+31s+39)