What is expand (x-1)/((x+3)(x-6)) ?

The solution to expand (x-1)/((x+3)(x-6)) is (x-1)/(x^2-3x-18)

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expand (x-1)/((x+3)(x-6))

expand

\frac{x - 1}{( x + 3 ) ( x - 6 )}

\frac{x - 1}{x ^{2} - 3 x - 18}

Solution steps

\frac{x - 1}{( x + 3 ) ( x - 6 )}

Expand

(x + 3) (x - 6) : x^{2} - 3 x - 18

= \frac{x - 1}{x ^{2} - 3 x - 18}

\frac{y x ^{2} - a}{( x + 2 y ) x ^{2}}

- \frac{2 ( - 3 x ^{2} - 5 )}{( - 5 + x ^{2} ) ^{3}}

(2 - cos (θ))^{2}

15 (- \frac{1}{2 t ^{2}} + \frac{1}{2})

\frac{2 ( sin ( 2 x ) + 1 )}{3 cos ^{2} ( 2 x )}

What is expand (x-1)/((x+3)(x-6)) ?
The solution to expand (x-1)/((x+3)(x-6)) is (x-1)/(x^2-3x-18)