What is expand (2(sin(2x)+1))/(3cos^2(2x)) ?

The solution to expand (2(sin(2x)+1))/(3cos^2(2x)) is (2sin(2x))/(3cos^2(2x))+2/(3cos^2(2x))

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expand (2(sin(2x)+1))/(3cos^2(2x))

expand

\frac{2 ( sin ( 2 x ) + 1 )}{3 cos ^{2} ( 2 x )}

\frac{2 sin ( 2 x )}{3 cos ^{2} ( 2 x )} + \frac{2}{3 cos ^{2} ( 2 x )}

Solution steps

\frac{2 ( sin ( 2 x ) + 1 )}{3 cos ^{2} ( 2 x )}

Expand

2 (sin (2 x) + 1) : 2 sin (2 x) + 2

= \frac{2 sin ( 2 x ) + 2}{3 cos ^{2} ( 2 x )}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 sin ( 2 x ) + 2}{3 cos ^{2} ( 2 x )} = \frac{2 sin ( 2 x )}{3 cos ^{2} ( 2 x )} + \frac{2}{3 cos ^{2} ( 2 x )}

= \frac{2 sin ( 2 x )}{3 cos ^{2} ( 2 x )} + \frac{2}{3 cos ^{2} ( 2 x )}

(x - \frac{3}{2}) (x - \frac{1}{2})

(15 + x) (\frac{15 + x}{2})^{2}

+ 10 y^{2} a t (2, 1, - 14)

\frac{4 x ^{2} + 16 x}{( x - 2 ) ^{2} ( x ^{2} + 4 )}

(\frac{1}{4} - x) (\frac{1}{4} + x)

What is expand (2(sin(2x)+1))/(3cos^2(2x)) ?
The solution to expand (2(sin(2x)+1))/(3cos^2(2x)) is (2sin(2x))/(3cos^2(2x))+2/(3cos^2(2x))