What is expand (8s(s+1)(s-6))/((s+2)(s+3)(s-7)) ?

The solution to expand (8s(s+1)(s-6))/((s+2)(s+3)(s-7)) is (8s^3-40s^2-48s)/(s^3-2s^2-29s-42)

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expand (8s(s+1)(s-6))/((s+2)(s+3)(s-7))

expand

\frac{8 s ( s + 1 ) ( s - 6 )}{( s + 2 ) ( s + 3 ) ( s - 7 )}

\frac{8 s ^{3} - 40 s ^{2} - 48 s}{s ^{3} - 2 s ^{2} - 29 s - 42}

Solution steps

\frac{8 s ( s + 1 ) ( s - 6 )}{( s + 2 ) ( s + 3 ) ( s - 7 )}

Expand

(s + 2) (s + 3) (s - 7) : s^{3} - 2 s^{2} - 29 s - 42

= \frac{8 s ( s + 1 ) ( s - 6 )}{s ^{3} - 2 s ^{2} - 29 s - 42}

Expand

8 s (s + 1) (s - 6) : 8 s^{3} - 40 s^{2} - 48 s

= \frac{8 s ^{3} - 40 s ^{2} - 48 s}{s ^{3} - 2 s ^{2} - 29 s - 42}

\frac{1}{( x - 1 ) ( x - 2 )}

\frac{m ^{2} + n ^{2}}{( m + n ) ^{2}}

A (4, - 6)

\frac{1}{3 ( 6 x ^{2} + 3 x - 9 )}

(m g r = m g h + \frac{m g h}{2}) \cdot \frac{1}{m g}

What is expand (8s(s+1)(s-6))/((s+2)(s+3)(s-7)) ?
The solution to expand (8s(s+1)(s-6))/((s+2)(s+3)(s-7)) is (8s^3-40s^2-48s)/(s^3-2s^2-29s-42)