What is expand ((10-3x)(x+1))/5 ?

The solution to expand ((10-3x)(x+1))/5 is -(3x^2)/5+(7x)/5+2

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expand ((10-3x)(x+1))/5

expand

\frac{( 10 - 3 x ) ( x + 1 )}{5}

- \frac{3 x ^{2}}{5} + \frac{7 x}{5} + 2

Solution steps

\frac{( 10 - 3 x ) ( x + 1 )}{5}

Expand

(10 - 3 x) (x + 1) : - 3 x^{2} + 7 x + 10

= \frac{- 3 x ^{2} + 7 x + 10}{5}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 x ^{2} + 7 x + 10}{5} = - \frac{3 x ^{2}}{5} + \frac{7 x}{5} + \frac{10}{5}

= - \frac{3 x ^{2}}{5} + \frac{7 x}{5} + \frac{10}{5}

Divide the numbers:

\frac{10}{5} = 2

= - \frac{3 x ^{2}}{5} + \frac{7 x}{5} + 2

10 (A \cdot cos (5 x) - A \cdot sin (5 x))

e^{(- 2 + i 25) \cdot 0.01}

\frac{d y ^{3}}{d ^{3} x} (y = cos (x) - ln (2 x))

lo g_{9} (x + 3) (x - 5)

(3 X + 2 Y - 16 = 0,) (5 X + 2 Y - (- 18) = 0)

What is expand ((10-3x)(x+1))/5 ?
The solution to expand ((10-3x)(x+1))/5 is -(3x^2)/5+(7x)/5+2