What is expand log_{9}(x+3)(x-5) ?

The solution to expand log_{9}(x+3)(x-5) is xlog_{9}(x+3)-5log_{9}(x+3)

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expand log_{9}(x+3)(x-5)

expand

lo g_{9} (x + 3) (x - 5)

x lo g_{9} (x + 3) - 5 lo g_{9} (x + 3)

Solution steps

lo g_{9} (x + 3) (x - 5)

Apply the distributive law:

a (b - c) = ab - a c

lo g_{9} (x + 3) (x - 5) = lo g_{9} (x + 3) x - lo g_{9} (x + 3) \cdot 5

= lo g_{9} (x + 3) x - lo g_{9} (x + 3) \cdot 5

= x lo g_{9} (x + 3) - 5 lo g_{9} (x + 3)

(3 X + 2 Y - 16 = 0,) (5 X + 2 Y - (- 18) = 0)

(ln (t))^{2}

(2 x + 2 y y^{'} (x) = 0) \frac{1}{2}

(1 + t)^{2} (1 - t)^{3}

37 - 2 (π x + π)^{3}

What is expand log_{9}(x+3)(x-5) ?
The solution to expand log_{9}(x+3)(x-5) is xlog_{9}(x+3)-5log_{9}(x+3)