What is expand (x-1)(ln(x-1)) ?

The solution to expand (x-1)(ln(x-1)) is xln(x-1)-ln(x-1)

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expand (x-1)(ln(x-1))

expand

(x - 1) (ln (x - 1))

x ln (x - 1) - ln (x - 1)

Solution steps

(x - 1) (ln (x - 1))

= (ln (x - 1)) (x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = (ln (x - 1)), b = x, c = 1

= (ln (x - 1)) x - (ln (x - 1)) \cdot 1

= x (ln (x - 1)) - 1 \cdot (ln (x - 1))

Simplify

x (ln (x - 1)) - 1 \cdot (ln (x - 1)) : x ln (x - 1) - ln (x - 1)

= x ln (x - 1) - ln (x - 1)

(4 x - 8 + 8 x) (h (x) = 2 x - 1)

(\frac{a}{x + 3} + \frac{b}{x - 2}) (x + 3) (x - 3)

(1.02)^{8}

\frac{( 2 x + 5 ) ^{2}}{x}

(3 + cos (x))^{3}

What is expand (x-1)(ln(x-1)) ?
The solution to expand (x-1)(ln(x-1)) is xln(x-1)-ln(x-1)