What are the solutions to the equation 3x^2+18x+33=6 ?

The solutions to the equation 3x^2+18x+33=6 are x=-3

Find the zeros of 3x^2+18x+33=6

The zeros of 3x^2+18x+33=6 are x=-3

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3 x^{2} + 18 x + 33 = 6

x = - 3

Solution steps

3 x^{2} + 18 x + 33 = 6

Move

6

to the left side

3 x^{2} + 18 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 27}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 27 = 0

x_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 3}

x = \frac{- 18}{2 \cdot 3}

\frac{- 18}{2 \cdot 3} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

\frac{- 4}{x ( x + 3 ) ( x - 1 ) ^{2}} \geq 0

x^{2} - 8 x + 20 = 5

a - 15 = 4 a - 3

x^{3} - 6 x^{2} > 0

\frac{7 0 ^{\frac{1}{3}}}{1 4 ^{\frac{1}{3}}}

What are the solutions to the equation 3x^2+18x+33=6 ?
The solutions to the equation 3x^2+18x+33=6 are x=-3
Find the zeros of 3x^2+18x+33=6
The zeros of 3x^2+18x+33=6 are x=-3