What is expand cos(3t-3)u(t-1)+t^3u(t-2) ?

The solution to expand cos(3t-3)u(t-1)+t^3u(t-2) is tucos(3t-3)-ucos(3t-3)+t^4u-2t^3u

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expand cos(3t-3)u(t-1)+t^3u(t-2)

expand

cos (3 t - 3) u (t - 1) + t^{3} u (t - 2)

t u cos (3 t - 3) - u cos (3 t - 3) + t^{4} u - 2 t^{3} u

Solution steps

cos (3 t - 3) u (t - 1) + t^{3} u (t - 2)

= u cos (3 t - 3) (t - 1) + t^{3} u (t - 2)

Expand

u cos (3 t - 3) (t - 1) : t u cos (3 t - 3) - u cos (3 t - 3)

= t u cos (3 t - 3) - u cos (3 t - 3) + t^{3} u (t - 2)

Expand

t^{3} u (t - 2) : t^{4} u - 2 t^{3} u

= t u cos (3 t - 3) - u cos (3 t - 3) + t^{4} u - 2 t^{3} u

\frac{d}{d r ( T )} ((E (r, T)) (10 - (10 T) (b^{- 0.14 r (T)})))

\frac{x ^{3} - 3 x ^{2}}{( x - 1 ) ^{3}}

(lo g_{10} (x)) (x + 1) (x + 2) (x + 3)

\frac{x ( x - y ln ( x ) )}{y ( y - x ln ( y ) )}

7 (10 + 3)

What is expand cos(3t-3)u(t-1)+t^3u(t-2) ?
The solution to expand cos(3t-3)u(t-1)+t^3u(t-2) is tucos(3t-3)-ucos(3t-3)+t^4u-2t^3u