What are the solutions to the equation (x-5)(x+1)=0 ?

The solutions to the equation (x-5)(x+1)=0 are x=5,x=-1

Find the zeros of (x-5)(x+1)=0

The zeros of (x-5)(x+1)=0 are x=5,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 5) (x + 1) = 0

x = 5, x = - 1

Solution steps

(x - 5) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 1 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 1 = 0 : x = - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

3 x^{2} + 22 x + 7

(4 a^{2} b)^{4} (\frac{- a ^{3}}{2 b})^{2}

x^{4} y^{3} - x y^{2}

6^{2} + 1 2^{2} = x^{2}

20 - 8

What are the solutions to the equation (x-5)(x+1)=0 ?
The solutions to the equation (x-5)(x+1)=0 are x=5,x=-1
Find the zeros of (x-5)(x+1)=0
The zeros of (x-5)(x+1)=0 are x=5,x=-1