What are the solutions to the equation 6^2+12^2=x^2 ?

The solutions to the equation 6^2+12^2=x^2 are x=6sqrt(5),x=-6sqrt(5)

Find the zeros of 6^2+12^2=x^2

The zeros of 6^2+12^2=x^2 are x=6sqrt(5),x=-6sqrt(5)

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6^{2} + 1 2^{2} = x^{2}

x = 65, x = - 65

Decimal Notation

x = 13.41640 \dots, x = - 13.41640 \dots

Solution steps

6^{2} + 1 2^{2} = x^{2}

Switch sides

x^{2} = 6^{2} + 1 2^{2}

Simplify

6^{2} + 1 2^{2} : 180

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 180, x = - 180

180 = 65

- 180 = - 65

x = 65, x = - 65

20 - 8

(2 + i)^{2} - (3 - i)^{2}

ln (e^{2})

6 x^{2} - 11 x + 3

1 2^{- \frac{1}{3}}

What are the solutions to the equation 6^2+12^2=x^2 ?
The solutions to the equation 6^2+12^2=x^2 are x=6sqrt(5),x=-6sqrt(5)
Find the zeros of 6^2+12^2=x^2
The zeros of 6^2+12^2=x^2 are x=6sqrt(5),x=-6sqrt(5)