What is (x-3)(x+1/4)(x-2)(x^2+1)(x+3) ?

The solution to (x-3)(x+1/4)(x-2)(x^2+1)(x+3) is ((x-3)(4x+1)(x-2)(x^2+1)(x+3))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x-3)(x+1/4)(x-2)(x^2+1)(x+3)

simplify

(x - 3) (x + \frac{1}{4}) (x - 2) (x^{2} + 1) (x + 3)

\frac{( x - 3 ) ( 4 x + 1 ) ( x - 2 ) ( x ^{2} + 1 ) ( x + 3 )}{4}

Solution steps

(x - 3) (x + \frac{1}{4}) (x - 2) (x^{2} + 1) (x + 3)

Simplify

x + \frac{1}{4} : \frac{4 x + 1}{4}

= (x - 3) \frac{4 x + 1}{4} (x - 2) (x^{2} + 1) (x + 3)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 3 ) ( 4 x + 1 ) ( x - 2 ) ( x ^{2} + 1 ) ( x + 3 )}{4}

\frac{1}{( ( 2 n - 1 ) ( 2 n + 1 ) ( 2 n + 3 ) )}

- 48 e^{2 t} \cdot U (t - 4)

(7 cos (θ) - 5 sin (θ))^{2}

\frac{3 x ^{2} - 6 x - 7}{( x + 4 ) ( x - 3 )}

(x^{2} - 2) (x + 1)

What is (x-3)(x+1/4)(x-2)(x^2+1)(x+3) ?
The solution to (x-3)(x+1/4)(x-2)(x^2+1)(x+3) is ((x-3)(4x+1)(x-2)(x^2+1)(x+3))/4