What is expand (-90I^2+90)/((I^2+I+1)^2) ?

The solution to expand (-90I^2+90)/((I^2+I+1)^2) is (-90I^2+90)/(I^4+2I^3+3I^2+2I+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (-90I^2+90)/((I^2+I+1)^2)

expand

\frac{- 90 I ^{2} + 90}{( I ^{2} + I + 1 ) ^{2}}

\frac{- 90 I ^{2} + 90}{I ^{4} + 2 I ^{3} + 3 I ^{2} + 2 I + 1}

Solution steps

\frac{- 90 I ^{2} + 90}{( I ^{2} + I + 1 ) ^{2}}

(I^{2} + I + 1)^{2} = I^{4} + 2 I^{3} + 3 I^{2} + 2 I + 1

= \frac{- 90 I ^{2} + 90}{I ^{4} + 2 I ^{3} + 3 I ^{2} + 2 I + 1}

\frac{d ^{2}}{d t ^{2}} ((x (t, y (x, t))) (4 y (x, t) + e^{t}))

\frac{1}{sin ( x ) - 1} + \frac{1}{1 + sin ( x )}

e^{x} (e^{x} - 2)

- 5^{n} + 7 (- 5^{n - 1})

\frac{d}{d t} ((C) (8000 + 2 x (C, t)))

What is expand (-90I^2+90)/((I^2+I+1)^2) ?
The solution to expand (-90I^2+90)/((I^2+I+1)^2) is (-90I^2+90)/(I^4+2I^3+3I^2+2I+1)