What is expand ((x^2+3x-28)(x-4))/(2x^3) ?

The solution to expand ((x^2+3x-28)(x-4))/(2x^3) is 1/2-1/(2x)-(20)/(x^2)+(56)/(x^3)

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expand ((x^2+3x-28)(x-4))/(2x^3)

expand

\frac{( x ^{2} + 3 x - 28 ) ( x - 4 )}{2 x ^{3}}

\frac{1}{2} - \frac{1}{2 x} - \frac{20}{x ^{2}} + \frac{56}{x ^{3}}

Solution steps

\frac{( x ^{2} + 3 x - 28 ) ( x - 4 )}{2 x ^{3}}

Expand

(x^{2} + 3 x - 28) (x - 4) : x^{3} - x^{2} - 40 x + 112

= \frac{x ^{3} - x ^{2} - 40 x + 112}{2 x ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - x ^{2} - 40 x + 112}{2 x ^{3}} = \frac{x ^{3}}{2 x ^{3}} - \frac{x ^{2}}{2 x ^{3}} - \frac{40 x}{2 x ^{3}} + \frac{112}{2 x ^{3}}

= \frac{x ^{3}}{2 x ^{3}} - \frac{x ^{2}}{2 x ^{3}} - \frac{40 x}{2 x ^{3}} + \frac{112}{2 x ^{3}}

\frac{x ^{3}}{2 x ^{3}} = \frac{1}{2}

\frac{x ^{2}}{2 x ^{3}} = \frac{1}{2 x}

\frac{40 x}{2 x ^{3}} = \frac{20}{x ^{2}}

\frac{112}{2 x ^{3}} = \frac{56}{x ^{3}}

= \frac{1}{2} - \frac{1}{2 x} - \frac{20}{x ^{2}} + \frac{56}{x ^{3}}

\frac{( 400 s - m g sin ( b ) )}{s \cdot ( m s ^{2} + b s )}

\frac{1}{20} + (1 - \frac{1}{20}) \cdot 0.5

(x^{2} + 6 \circ x^{2} - 1) (x)

(x + \frac{1}{2}) (x + 1)

\frac{1 - x ^{2}}{3 - x ^{- 1}}

What is expand ((x^2+3x-28)(x-4))/(2x^3) ?
The solution to expand ((x^2+3x-28)(x-4))/(2x^3) is 1/2-1/(2x)-(20)/(x^2)+(56)/(x^3)