What is expand (a^{3/5}-b^{3/5})^2 ?

The solution to expand (a^{3/5}-b^{3/5})^2 is a^{6/5}-2a^{3/5}b^{3/5}+b^{6/5}

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expand (a^{3/5}-b^{3/5})^2

expand

(a^{\frac{3}{5}} - b^{\frac{3}{5}})^{2}

a^{\frac{6}{5}} - 2 a^{\frac{3}{5}} b^{\frac{3}{5}} + b^{\frac{6}{5}}

Solution steps

(a^{\frac{3}{5}} - b^{\frac{3}{5}})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(a^{\frac{3}{5}} - b^{\frac{3}{5}})^{2} = (a^{\frac{3}{5}})^{2} - 2 a^{\frac{3}{5}} b^{\frac{3}{5}} + (b^{\frac{3}{5}})^{2}

= (a^{\frac{3}{5}})^{2} - 2 a^{\frac{3}{5}} b^{\frac{3}{5}} + (b^{\frac{3}{5}})^{2}

(a^{\frac{3}{5}})^{2} = a^{\frac{6}{5}}

(b^{\frac{3}{5}})^{2} = b^{\frac{6}{5}}

= a^{\frac{6}{5}} - 2 a^{\frac{3}{5}} b^{\frac{3}{5}} + b^{\frac{6}{5}}

\frac{( x ^{5} )}{x ^{2}}

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(2 x + 3 y = 6,) (4 x + 6 y = 12)

(2 x y + z^{2}) (3 cos (t))

(\frac{7}{x ^{3}} + 5 x^{5})^{5}

What is expand (a^{3/5}-b^{3/5})^2 ?
The solution to expand (a^{3/5}-b^{3/5})^2 is a^{6/5}-2a^{3/5}b^{3/5}+b^{6/5}