What is expand (4(x^2-4x-1))/((x-1)^2(x+3)^2) ?

The solution to expand (4(x^2-4x-1))/((x-1)^2(x+3)^2) is (4x^2-16x-4)/(x^4+4x^3-2x^2-12x+9)

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expand (4(x^2-4x-1))/((x-1)^2(x+3)^2)

expand

\frac{4 ( x ^{2} - 4 x - 1 )}{( x - 1 ) ^{2} ( x + 3 ) ^{2}}

\frac{4 x ^{2} - 16 x - 4}{x ^{4} + 4 x ^{3} - 2 x ^{2} - 12 x + 9}

Solution steps

\frac{4 ( x ^{2} - 4 x - 1 )}{( x - 1 ) ^{2} ( x + 3 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{4 ( x ^{2} - 4 x - 1 )}{( x ^{2} - 2 x + 1 ) ( x + 3 ) ^{2}}

(x + 3)^{2} = x^{2} + 6 x + 9

= \frac{4 ( x ^{2} - 4 x - 1 )}{( x ^{2} - 2 x + 1 ) ( x ^{2} + 6 x + 9 )}

Expand

(x^{2} - 2 x + 1) (x^{2} + 6 x + 9) : x^{4} + 4 x^{3} - 2 x^{2} - 12 x + 9

= \frac{4 ( x ^{2} - 4 x - 1 )}{x ^{4} + 4 x ^{3} - 2 x ^{2} - 12 x + 9}

Expand

4 (x^{2} - 4 x - 1) : 4 x^{2} - 16 x - 4

= \frac{4 x ^{2} - 16 x - 4}{x ^{4} + 4 x ^{3} - 2 x ^{2} - 12 x + 9}

(11 - 44 i) (1 - 2 i)

\frac{1}{2 ( x - 5 )}

2 x - y (y + Δ y)

arctan (x) (- x + tan (x))

i e^{(- 2 + i 100) t}

What is expand (4(x^2-4x-1))/((x-1)^2(x+3)^2) ?
The solution to expand (4(x^2-4x-1))/((x-1)^2(x+3)^2) is (4x^2-16x-4)/(x^4+4x^3-2x^2-12x+9)