What is expand F_{1}(3,-2)yF_{2}(3,4) ?

The solution to expand F_{1}(3,-2)yF_{2}(3,4) is 3(3*4,)F_{1}yF_{2},-2(3*4,)F_{1}yF_{2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand F_{1}(3,-2)yF_{2}(3,4)

expand

F_{1} (3, - 2) y F_{2} (3, 4)

3 (3 \cdot 4,) F_{1} y F_{2}, - 2 (3 \cdot 4,) F_{1} y F_{2}

Solution steps

F_{1} (3, - 2) y F_{2} (3, 4)

= (3, - 2) (3 \cdot 4,) F_{1} y F_{2}

Apply the distributive law:

a (b - c) = ab - a c

a = F_{1} y F_{2} (3, 4), b = 3,, c = 2

= F_{1} y F_{2} (3, 4) \cdot 3, - F_{1} y F_{2} (3, 4) \cdot 2

= 3 (3 \cdot 4,) F_{1} y F_{2}, - 2 (3 \cdot 4,) F_{1} y F_{2}

(x + 5) (3 x - 2) (x + 2 + i) (x - 2 + i)

4 (6 x - 5 y = 28)

\frac{( ( 4 - x ^{2} ) ^{4} )}{2}

(x + 1) (\frac{2 x}{x + 1} + 1)

\frac{5 x + 13}{( 2 x + 1 ) ( x + 4 )}

What is expand F_{1}(3,-2)yF_{2}(3,4) ?
The solution to expand F_{1}(3,-2)yF_{2}(3,4) is 3(3*4,)F_{1}yF_{2},-2(3*4,)F_{1}yF_{2}