What is expand (x^2-3x-4)/((x-1)(x+2)^2) ?

The solution to expand (x^2-3x-4)/((x-1)(x+2)^2) is (x^2-3x-4)/(x^3+3x^2-4)

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expand (x^2-3x-4)/((x-1)(x+2)^2)

expand

\frac{x ^{2} - 3 x - 4}{( x - 1 ) ( x + 2 ) ^{2}}

\frac{x ^{2} - 3 x - 4}{x ^{3} + 3 x ^{2} - 4}

Solution steps

\frac{x ^{2} - 3 x - 4}{( x - 1 ) ( x + 2 ) ^{2}}

(x + 2)^{2} = x^{2} + 4 x + 4

= \frac{x ^{2} - 3 x - 4}{( x - 1 ) ( x ^{2} + 4 x + 4 )}

Expand

(x - 1) (x^{2} + 4 x + 4) : x^{3} + 3 x^{2} - 4

= \frac{x ^{2} - 3 x - 4}{x ^{3} + 3 x ^{2} - 4}

- 36 h (8 h - h^{2})

V^{2} + 2 a (x - y)

42 + 36

\frac{1}{2} (arcsin (x - 1) + \frac{1}{2} sin (2 arcsin (x - 1)))

\frac{x ^{3}}{4} (\frac{3}{x} - sin (\frac{3}{x}))

What is expand (x^2-3x-4)/((x-1)(x+2)^2) ?
The solution to expand (x^2-3x-4)/((x-1)(x+2)^2) is (x^2-3x-4)/(x^3+3x^2-4)