What is expand 4(6-x-2(3-x-5=9(5-2x))) ?

The solution to expand 4(6-x-2(3-x-5=9(5-2x))) is 4*6-4x+8x+336=5-2x

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expand 4(6-x-2(3-x-5=9(5-2x)))

expand

4 (6 - x - 2 (3 - x - 5 = 9 (5 - 2 x)))

4 \cdot 6 - 4 x + 8 x + 336 = 5 - 2 x

Solution steps

4 (6 - x - 2 (3 - x - 5 = 9 (5 - 2 x)))

= 4 (6 - x - 2 (3 - x - 5 \cdot 9 = (5 - 2 x)))

Expand

4 (6 - x - 2 (3 - x - 5 = 9 (5 - 2 x))) : 4 \cdot 6 - 4 x - 4 \cdot 2 (3 - x - 5 \cdot 9 = (5 - 2 x))

= 4 \cdot 6 - 4 x - 4 \cdot 2 (3 - x - 5 \cdot 9 = (5 - 2 x))

Expand

- 4 \cdot 2 (3 - x - 5 \cdot 9 = (5 - 2 x)) : 8 x + 336 = 5 - 2 x

4 \cdot 6 - 4 x + 8 x + 336 = 5 - 2 x

\frac{2 x - 6}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}}

10 [lo g_{10} (\frac{I}{1 0 ^{- 12}})]

(2 p - 0.8) (2 p - 0, 5)

(3 x - \frac{1}{3})^{3}

What is expand 4(6-x-2(3-x-5=9(5-2x))) ?
The solution to expand 4(6-x-2(3-x-5=9(5-2x))) is 4*6-4x+8x+336=5-2x