What is expand (2(3x+8)(3x-8))/(3(x+2)(x-2)) ?

The solution to expand (2(3x+8)(3x-8))/(3(x+2)(x-2)) is (18x^2-128)/(3x^2-12)

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expand (2(3x+8)(3x-8))/(3(x+2)(x-2))

expand

\frac{2 ( 3 x + 8 ) ( 3 x - 8 )}{3 ( x + 2 ) ( x - 2 )}

\frac{18 x ^{2} - 128}{3 x ^{2} - 12}

Solution steps

\frac{2 ( 3 x + 8 ) ( 3 x - 8 )}{3 ( x + 2 ) ( x - 2 )}

Expand

3 (x + 2) (x - 2) : 3 x^{2} - 12

= \frac{2 ( 3 x + 8 ) ( 3 x - 8 )}{3 x ^{2} - 12}

Expand

2 (3 x + 8) (3 x - 8) : 18 x^{2} - 128

= \frac{18 x ^{2} - 128}{3 x ^{2} - 12}

\frac{x + x ^{\frac{1}{3}} ( x - 3 )}{x - 3} + x

e (4 - 3 x)

2 cos (t) (2 sin (t) - 9 tan (t))

\frac{4 ( n + 1 )}{n}

P (0, - 4) Q (- 3, 0)

What is expand (2(3x+8)(3x-8))/(3(x+2)(x-2)) ?
The solution to expand (2(3x+8)(3x-8))/(3(x+2)(x-2)) is (18x^2-128)/(3x^2-12)