What is (\partial)/(\partial y)((m)(x+y)dx) ?

The answer to (\partial)/(\partial y)((m)(x+y)dx) is mxd

Popular >

(\partial)/(\partial y)((m)(x+y)dx)

\frac{\partial}{\partial y} ((m) (x + y) d x)

m x d

Solution steps

\frac{\partial}{\partial y} ((m) (x + y) d x)

Treat

m, x, d

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= m d x \frac{\partial}{\partial y} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= m d x (\frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y))

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

= m d x (0 + 1)

Simplify

= m x d

\frac{lo g _{10} ( x ) ( x ^{2} + 6 ) - 1}{2}

(2 + 5) (3 + 7)

\frac{( 3 - 2 j ) ( 8 + 10 j )}{( 11 + 8 i )}

\frac{( 2 - x ) ^{3} \cdot ( 9 - x ) ^{5}}{( x ^{2} + 8 ) ^{2}}

\frac{7 ( n + 1 ) ^{2}}{4 n}

What is (\partial)/(\partial y)((m)(x+y)dx) ?
The answer to (\partial)/(\partial y)((m)(x+y)dx) is mxd