What is expand (6x^2+8x-24)/(2x) ?

The solution to expand (6x^2+8x-24)/(2x) is 3x+4-(12)/x

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expand (6x^2+8x-24)/(2x)

expand

\frac{6 x ^{2} + 8 x - 24}{2 x}

3 x + 4 - \frac{12}{x}

Solution steps

\frac{6 x ^{2} + 8 x - 24}{2 x}

Factor

6 x^{2} + 8 x - 24 : 2 (3 x^{2} + 4 x - 12)

= \frac{2 ( 3 x ^{2} + 4 x - 12 )}{2 x}

Divide the numbers:

\frac{2}{2} = 1

= \frac{3 x ^{2} + 4 x - 12}{x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} + 4 x - 12}{x} = \frac{3 x ^{2}}{x} + \frac{4 x}{x} - \frac{12}{x}

= \frac{3 x ^{2}}{x} + \frac{4 x}{x} - \frac{12}{x}

Cancel

\frac{3 x ^{2}}{x} : 3 x

= 3 x + \frac{4 x}{x} - \frac{12}{x}

Cancel

\frac{4 x}{x} : 4

= 3 x + 4 - \frac{12}{x}

(24 sin (x) + 6 sin (2 x))^{2}

\frac{d}{d q} ((c) (0.2 q^{2} + 2 q + 500))

(y = 2 - x) (0.5)

(- 4, - 5) y (6, - 1)

\frac{- 7 x ^{8} + 9}{( x ^{8} + 9 ) ^{2}}

What is expand (6x^2+8x-24)/(2x) ?
The solution to expand (6x^2+8x-24)/(2x) is 3x+4-(12)/x